
01:26
yes

01:26
yes

01:28
yes

02:24
sheet 12

02:25
this week, the new one please

02:25
sheet 11 please

02:26
Next Sheet please

02:28
new one

02:31
11

02:34
sheet 12 please

02:35
new one

02:37
Excercise 4 of sheet 11

04:37
not quite

06:56
which notation do you mean?

08:58
yes

14:59
yes

20:10
yes

21:44
yes

23:45
yes

25:11
yes

25:48
yes

31:40
if we calculated e^tA via the diagonalisation, can we find the solution for the initial value problem by multiplying e^tA * initial value?

33:39
yes perfect

33:43
thank you

39:17
1 false

43:11
can you explain sheet 11 ex 3.4

43:45
yes

44:35
yes

49:49
Yes thank you very much

52:43
yes thank you

53:04
bye thanks a lot!

53:06
thank you very much

53:11
bye thanks!

53:19
is there going to be a sheet 13?

53:30
ok:) thanks:)